There are 4 ways to get from Keighley to Haworth by bus, taxi, towncar or foot
Select an option below to see step-by-step directions and to compare ticket prices and travel times in Rome2rio's travel planner.
Bus • 11m
$1 - $3
3 alternative options
Taxi • 6m
$15 - $19
Uber • 6m
$6 - $10
Walk • 1h 2m
Questions & Answers
The cheapest way to get from Keighley to Haworth is to bus which costs £1 - £2 and takes 11m.
The quickest way to get from Keighley to Haworth is to taxi which costs £12 - £15 and takes 6m.
Yes, there is a direct bus departing from Keighley, Bus Station station and arriving at Lees Lane Lawcliffe Ln. Services depart every 30 minutes, and operate every day. The journey takes approximately 11m.
The distance between Keighley and Haworth is 3 miles.
The best way to get from Keighley to Haworth without a car is to bus which takes 11m and costs £1 - £2.
The bus from Keighley, Bus Station to Lees Lane Lawcliffe Ln takes 11m including transfers and departs every 30 minutes.
Keighley to Haworth bus services, operated by Keighley & District, arrive at Keighley, Bus Station.
Keighley to Haworth bus services, operated by Keighley & District, arrive at Lees Lane Lawcliffe Ln station.
There are 592+ hotels available in Haworth. Prices start at $65 USD per night.
What companies run services between Keighley, England and Haworth, England?
Keighley & District operates a bus from Keighley to Haworth every 30 minutes. Tickets cost $1 - $3 and the journey takes 11m.
Bus from Keighley, Bus Station to Lees Lane Lawcliffe Ln
- Ave. Duration
- Every 30 minutes
- Estimated price
- $1 - $3
- Schedules at
Want to know more about travelling around United Kingdom
Rome2rio's Travel Guide series provide vital information for the global traveller. Filled with useful and timely travel information, the guides answer all the hard questions - such as 'How do I buy a ticket?', 'Should I book online before I travel? ', 'How much should I expect to pay?', 'Do the trains and buses have Wifi?' - to help you get the most out of your next trip.