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Villanova University to Secaucus Junction trains

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Trip Overview

The average train between Villanova University and Secaucus Junction takes 2h 25m and the fastest train takes 1h 44m. The train service runs several times per day from Villanova University to Secaucus Junction. The journey time may be longer on weekends and holidays; use the search form on this page to search for a specific travel date.

2h 25m
Duration
97 mi
Distance
$157
Average price
Every 4 hours
Frequency

Villanova University to Secaucus Junction train times

Trains run every 4 hours between Villanova University and Secaucus Junction. The earliest departure is at 4:17 PM in the afternoon, and the last departure from Villanova University is at 11:02 PM which arrives into Secaucus Junction at 5:03 AM. All services require a transfer at Villanova and take an average of 2h 25m. The schedules shown below are for the next available departures.

Frequently asked questions

Want to know about travelling from Villanova University to Secaucus Junction? We have put together a list of the most frequently asked questions from our users such as: What is the cheapest mode of transport? What is the quickest option? How much do tickets usually cost? and many more.

Map of how to get from Villanova University to Secaucus Junction.ExpandLaunch map view
  • Distance: 96.6 mi
  • Duration: 2h 25m

What companies run services between Villanova University, PA, USA and Secaucus Junction, NJ, USA?

You can take a vehicle from Villanova University to Secaucus Upper Level via Villanova, 30th Street Station, and Newark Penn Station in around 2h 10m.

Operators