The average train between Secaucus Junction and Bloomfield takes 21 min and the fastest train takes 19 min. There is a train service every few hours from Secaucus Junction to Bloomfield. The journey time may be longer on weekends and holidays; use the search form on this page to search for a specific travel date.
Trains run hourly between Secaucus Junction and Bloomfield. The earliest departure is at 12:43 AM at night, and the last departure from Secaucus Junction is at 11:51 PM which arrives into Bloomfield at 12:12 AM. All services run direct with no transfers required, and take on average 21 min. The schedules shown below are for the next available departures.
Want to know about travelling from Secaucus Junction to Bloomfield? We have put together a list of the most frequently asked questions from our users such as: What is the cheapest mode of transport? What is the quickest option? How much do tickets usually cost? and many more.
Yes, there is a direct train departing from Secaucus Junction station and arriving at Bloomfield station. Services depart hourly, and operate 5 times a week. The journey takes approximately 21 min.
Secaucus Junction to Bloomfield train services, operated by NJ Transit, depart from Secaucus Upper Level station.
Secaucus Junction to Bloomfield train services, operated by NJ Transit, arrive at Glen Ridge station.
The distance between Secaucus Junction and Bloomfield is 10.5 km. The road distance is 16 km.
NJ Transit operates a train from Secaucus Upper Level to Glen Ridge hourly. Tickets cost $2–11 and the journey takes 22 min.