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Schenectady to Port Jefferson trains

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Trip Overview

The average train between Schenectady and Port Jefferson takes 7h 16m and the fastest train takes 5h 46m. The train service runs several times per day from Schenectady to Port Jefferson. The journey time may be longer on weekends and holidays; use the search form on this page to search for a specific travel date.

7h 16m
Duration
218 mi
Distance
$95
Average price
4 times a day
Frequency

Schenectady to Port Jefferson train times

Trains run 4 times a day between Schenectady and Port Jefferson. The earliest departure is at 9:21 AM in the morning, and the last departure from Schenectady is at 6:38 PM which arrives into Port Jefferson at 2:35 AM. All services require a transfer at Albany-Rensselaer Amtrak Station and take an average of 7h 16m. The schedules shown below are for the next available departures.

Frequently asked questions

Want to know about travelling from Schenectady to Port Jefferson? We have put together a list of the most frequently asked questions from our users such as: What is the cheapest mode of transport? What is the quickest option? How much do tickets usually cost? and many more.

Map of how to get from Schenectady to Port Jefferson.ExpandLaunch map view
  • Distance: 218.2 mi
  • Duration: 7h 16m

What companies run services between Schenectady, NY, USA and Port Jefferson, NY, USA?

You can take a train from Schenectady to Port Jefferson via Albany-Rensselaer Amtrak Station, Ny Moynihan Train Hall At Penn Station, New York Penn Station, and Jamaica in around 6h 34m.

Operators