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Manosque to Lure trains

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Trip Overview

The average train between Manosque and Lure takes 12h 12m and the fastest train takes 7h 24m. The train service runs several times per day from Manosque to Lure. The journey time may be longer on weekends and holidays; use the search form on this page to search for a specific travel date.

12h 12m
Duration
800 km
Distance
€196
Average price
Twice daily
Frequency

Train

best
  1. Take the train from Manosque Greoux Les Bains to Marseille St Charlestrain train Ter
  2. Take the train from Marseille St Charles to Belfort-Montbeliard Tgvtrain train Tgv
7h 55m
€163–276

Manosque to Lure train times

Trains run twice daily between Manosque and Lure. The earliest departure is at 6:25 AM in the morning, and the last departure from Manosque is at 11:28 AM which arrives into Lure at 8:04 AM. All services require a transfer at Marseille St Charles and take an average of 12h 12m. The schedules shown below are for the next available departures.

Frequently asked questions

Want to know about travelling from Manosque to Lure? We have put together a list of the most frequently asked questions from our users such as: What is the cheapest mode of transport? What is the quickest option? How much do tickets usually cost? and many more.

Map of how to get from Manosque to Lure.ExpandLaunch map view
  • Distance: 799.7 km
  • Duration: 12h 12m

What companies run services between Manosque, France and Lure, Bourgogne-Franche-Comté, France?

You can take a train from Manosque Greoux Les Bains to Lure via Marseille St Charles, Belfort-Montbeliard Tgv, Meroux, and Belfort in around 7h 55m.

Operators