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Jenbach to Belgrade trains

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Trip Overview

The average train between Jenbach and Belgrade takes 22h 46m and the fastest train takes 22h 6m. The train runs, on average, 6 times per week from Jenbach to Belgrade. The journey time may be longer on weekends and holidays; use the search form on this page to search for a specific travel date.

22h 46m
Duration
1,134 km
Distance
RSD 19,135
Average price
6 times a week
Frequency

Jenbach to Belgrade train times

Trains run 6 times a week between Jenbach and Belgrade. The earliest departure is at 9:13 AM in the morning, and the last departure from Jenbach is at 11:13 AM which arrives into Belgrade at 9:19 AM. All services require a transfer at Wien Hbf and take an average of 22h 46m. The schedules shown below are for the next available departures.

Frequently asked questions

Want to know about travelling from Jenbach to Belgrade? We have put together a list of the most frequently asked questions from our users such as: What is the cheapest mode of transport? What is the quickest option? How much do tickets usually cost? and many more.

Map of how to get from Jenbach to Belgrade.ExpandLaunch map view
  • Distance: 1,133.9 km
  • Duration: 22h 46m

What companies run services between Jenbach, Austria and Belgrade, Serbia?

You can take a train from Jenbach to Beograd Centar via Wien Hbf, Budapest-Kelenfoeld, Szeged, and Subotica in around 15h 11m.

Operators