The average train between Bloomfield and Secaucus Junction takes 23 min and the fastest train takes 20 min. There is a train service every few hours from Bloomfield to Secaucus Junction. The journey time may be longer on weekends and holidays; use the search form on this page to search for a specific travel date.
Trains run hourly between Bloomfield and Secaucus Junction. The earliest departure is at 5:30 AM in the morning, and the last departure from Bloomfield is at 11:28 PM which arrives into Secaucus Junction at 11:51 PM. All services run direct with no transfers required, and take on average 23 min. The schedules shown below are for the next available departures.
Want to know about travelling from Bloomfield to Secaucus Junction? We have put together a list of the most frequently asked questions from our users such as: What is the cheapest mode of transport? What is the quickest option? How much do tickets usually cost? and many more.
Yes, there is a direct train departing from Bloomfield station and arriving at Secaucus Junction station. Services depart hourly, and operate 5 times a week. The journey takes approximately 23 min.
Bloomfield to Secaucus Junction train services, operated by NJ Transit, depart from Glen Ridge station.
Bloomfield to Secaucus Junction train services, operated by NJ Transit, arrive at Secaucus Upper Level station.
The distance between Bloomfield and Secaucus Junction is 10.5 km. The road distance is 16 km.
NJ Transit operates a train from Glen Ridge to Secaucus Upper Level every 2 hours. Tickets cost $2–11 and the journey takes 23 min.